pertanyaan di Tentukan pH larutan NH CI 0,42 M (K, NH,OH = 1,8 x 10-6)! Jawab:
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Jawaban:
pH = 4,5 - log [tex]\sqrt{2}[/tex]
Penjelasan:
[H+] = [tex]\sqrt{\frac{Kw}{Kb} . M. valensi garam } = \sqrt{\frac{10^{-14}}{1,8 . 10^{-6}} . 0,42 . 1 } = \sqrt{2 . 10^{-9} } = 10^{-4,5}\sqrt{2}[/tex]
pH = 4,5 - log [tex]\sqrt{2}[/tex]
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